Kepler

logistic_guy

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Use Kepler\displaystyle \text{Kepler}'s laws and the period of the Moon (27.4 d)\displaystyle (27.4 \ \text{d}) to determine the period of an artificial satellite orbiting very near the Earth's surface.
 
Use Kepler\displaystyle \text{Kepler}'s laws and the period of the Moon (27.4 d)\displaystyle (27.4 \ \text{d}) to determine the period of an artificial satellite orbiting very near the Earth's surface.
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Kepler's third law is suffice to solve this problem.

T2=4π2r3GmE\displaystyle T^2 = \frac{4\pi^2 r^3}{Gm_E}

This gives:

(TSTMoon)2=(rSrMoon)3\displaystyle \left(\frac{T_S}{T_{\text{Moon}}}\right)^2 = \left(\frac{r_S}{r_{\text{Moon}}}\right)^3

where rMoon\displaystyle r_{\text{Moon}} is the average distance from the Earth to the Moon.

Plug in numbers.

(TS27.4)2=(6.38×1063.84×108)3\displaystyle \left(\frac{T_S}{27.4}\right)^2 = \left(\frac{6.38 \times 10^{6}}{3.84 \times 10^8}\right)^3

This gives:

TS=0.0586793 d=1.41 h\displaystyle T_S = 0.0586793 \ \text{d} = \textcolor{blue}{1.41 \ \text{h}}
 
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