kinetic energy of mass 1.6 * 10^3 kg travelling at 3.4 * 10^3 m/s

[AxoPax]

The expression \(\displaystyle \frac{1}{2}mv^2\) gives the kinetic energy, in joules, of an object with a mass of m kilograms travelling at a speed of v meters per second. What is the kinetic energy of an experimental unmanned jet with a mass of 1.6 × 10³ kg travelling at a speed of about 3.4 × 10³ m/s?

 

[Deleted member 4993]

The expression \(\displaystyle \frac{1}{2}mv^2\) gives the kinetic energy, in joules, of an object with a mass of m kilograms travelling at a speed of v meters per second. What is the kinetic energy of an experimental unmanned jet with a mass of 1.6 × 10³ kg travelling at a speed of about 3.4 × 10³ m/s?

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[AxoPax]

I formed a initial equation, 1/2mv^2 = (1.6*10^3)(3.4*10^3)^2

But I don't know how to proceed from here

 

[Harry_the_cat]

I formed a initial equation, 1/2mv^2 = (1.6*10^3)(3.4*10^3)^2

But I don't know how to proceed from here

Firstly you've missed the 1/2 on the RHS.

\(\displaystyle \frac{1}{2}*(1.6*10^3)*(3.4*10^3)^2\)

\(\displaystyle = \frac{1}{2}*1.6*10^3*3.4^2*(10^3)^2\) ...... using the rule \(\displaystyle (a*b)^n = a^n*b^n\)

\(\displaystyle = \frac{1}{2}*1.6*3.4^2*10^3*10^6\) ...... using the rule \(\displaystyle (a^m)^n = a^{m*n}\)

Can you finish it from there?