Lagrange with e^-xy

engineertobe

New member
Joined
Oct 8, 2011
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20
Find the extreme values of f(x
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y)=exy
on the region described by x2+25y2
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16


I can get to -ye^(-xy)= λ2x, -xe^(-xy)= λ50y but then I do not know how to solve for λ so I become stuck
 
You have \(\displaystyle -ye^{-xy}=2x\lambda\Rightarrow \lambda=\frac{-ye^{-xy}}{2x}\)

\(\displaystyle -xe^{-xy}=50y\lambda\Rightarrow \lambda = \frac{-xe^{-xy}}{50y}\)

\(\displaystyle \frac{-ye^{-xy}}{2x}=\frac{-xe^{-xy}}{50y}\)

\(\displaystyle \frac{-y}{2x}=\frac{-x}{50y}\)

\(\displaystyle x=\pm 5y\)

Now, sub into the constraint and find x and y.
 
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