B blitzen New member Joined Jan 7, 2011 Messages 14 Jan 9, 2011 #1 I know that there is a division rule with the logarithms, but I have a question in regards to if I am correct with this: If I have the ln (sq rt. [(x+7) / (x-8)] ) Would that give me ln (sq. rt. (x + 7)) - ln (sq. rt. (x - 8)) ?
I know that there is a division rule with the logarithms, but I have a question in regards to if I am correct with this: If I have the ln (sq rt. [(x+7) / (x-8)] ) Would that give me ln (sq. rt. (x + 7)) - ln (sq. rt. (x - 8)) ?
mmm4444bot Super Moderator Joined Oct 6, 2005 Messages 10,958 Jan 9, 2011 #2 Yes, for all valid values of x. If you're savvy with graphing technology, you might have graphed both expressions to verify this identity. BTW, we can text square-root notation like so: ln[sqrt({x + 7}/{x - 8})] = ln[sqrt(x + 7)] - ln[sqrt(x - 8)]
Yes, for all valid values of x. If you're savvy with graphing technology, you might have graphed both expressions to verify this identity. BTW, we can text square-root notation like so: ln[sqrt({x + 7}/{x - 8})] = ln[sqrt(x + 7)] - ln[sqrt(x - 8)]