Legendre's equation

logistic_guy

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Joined
Apr 17, 2024
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901
Solve.

(1x2)y2xy+2y=0\displaystyle (1 - x^2)y'' - 2xy' + 2y = 0
 
Solve.

(1x2)y2xy+2y=0\displaystyle (1 - x^2)y'' - 2xy' + 2y = 0
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