Length in 1st quadrant of circle r=sin ? + cos ?

[MAC-A-TAC]

I need help finishing the solution to the attached problem.
Am I correct in my solution thus far? :?
Thank you for your help.

 

[Deleted member 4993]

I need help finishing the solution to the attached problem.
Am I correct in my solution thus far? :? >>>> No
Thank you for your help.

[2 cos(x) - 4 sin(x)][sup:2zz575mx]2[/sup:2zz575mx] + [2 sin(x) + 4 cos(x)][sup:2zz575mx]2[/sup:2zz575mx]

= 4 cos[sup:2zz575mx]2[/sup:2zz575mx](x) - 16 sin(x)cos(x) + 16sin[sup:2zz575mx]2[/sup:2zz575mx](x)
+4 sin[sup:2zz575mx]2[/sup:2zz575mx](x) + 16 sin(x)cos(x) + 16cos[sup:2zz575mx]2[/sup:2zz575mx](x)

= 4 + 16 = 20

 

[MAC-A-TAC]

Thank you for the review.
I need to slow down.

 

[MAC-A-TAC]

Would someone please walk me through the solution for the attached problem.
I am at the point in the solution where I am trying to clear the radical.

Thank you for your help.

 

[daon]

Hintaroo: \(\displaystyle cos^2\theta + sin^2\theta = 1\)

 

[Deleted member 4993]

Duplicate post:

viewtopic.php?f=3&t=33208

 

[MAC-A-TAC]

Still require help on this.
I tried that and end up with 2?5 which does not allow me to plug in the limits because there is no variable.

Thank you for your help.

 

[fasteddie65]

When you simplify, you have ? 2?5 dø, which is 2?5 ø, very easy to evaluate.