Let b3 - a3 = (b - a)(a2 + ab + b2). The inverse of 3 1/2 is given by

abel muroi

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Jan 13, 2015
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I was given this problem..

Let b3 - a3 = (b - a)(a2 + ab + b2). The inverse of 3 1/2 is given by...


A. f-1 (x) = -(x+1)/(x-1)

B. f(x) = (x - 1)/(x + 1)

C. (a, 4)


How can I begin to solve this?
 
I was given this problem..

Let b3 - a3 = (b - a)(a2 + ab + b2). The inverse of 3 1/2 is given by...


A. f-1 (x) = -(x+1)/(x-1)

B. f(x) = (x - 1)/(x + 1)

C. (a, 4)


How can I begin to solve this?
I'm not understanding your question. In the first place the
b3 - a3 = (b - a)(a2 + ab + b2)
is an identity so there is no Let ... Next, is the 3 1/2 supposed to represent the usual real number 3.5=7/2=... If so, the choices seem to me to have nothing to do with the inverse of 3 1/2.

Is there, perchance, more to the question that you can post, a posting of the exact question may clear up some of the mystery. Oh, and you might also read
http://www.freemathhelp.com/forum/threads/78006-Read-Before-Posting
 
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