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logistic_guy

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At what angle will 440\displaystyle 440-nm\displaystyle \text{nm} light produce a third-order maximum when falling on a grating whose slits are 1.35×103 cm\displaystyle 1.35 \times 10^{-3} \ \text{cm} apart?
 
At what angle will 440\displaystyle 440-nm\displaystyle \text{nm} light produce a third-order maximum when falling on a grating whose slits are 1.35×103 cm\displaystyle 1.35 \times 10^{-3} \ \text{cm} apart?
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We use the diffraction maxima formula.

dsinθ=mλ\displaystyle d\sin \theta = m\lambda

Third-order means m=3\displaystyle m = 3, then

1.35×105sinθ=3(440×109)\displaystyle 1.35 \times 10^{-5}\sin \theta = 3(440 \times 10^{-9})

This gives:

sinθ=0.0977778\displaystyle \sin\theta = 0.0977778

θ=sin10.0977778=5.61\displaystyle \theta = \sin^{-1} 0.0977778 = 5.61^{\circ}
 
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