Limit as it approaches 0

[gmontalv]

lim (x+h)^2 -x^2
h->0 -----------------
h

The answer to this is 2x however I don't know how they got this!

 

[Daniel_Feldman]

Multiply out (x+h)^2, and simplify.

 

[Matt]

lim        (x+h)^2 -x^2
h->0     -----------------      
                 h

The answer to this is 2x however I don't know how they got this!

What you should do first is simplify the expression:

\(\displaystyle \L\qquad\begin{eqnarray}
\frac{(x+h)^2-x^2}{h}
&=&\frac{x^2+2xh+h^2-x^2}{h}\\
&=&\frac{2xh+h^2}{h}\\
&=&2x+h
\end{eqnarray}\)

Now take the limit as h->0.

 

[gmontalv]

Thanks

Thanks!!! :lol: