Limit Comparison Test for sum[n=1,infty][e^(1/n)]

[maeveoneill]

Determine whether the series is convergent or divergent.

infinity
---
\ e^(1/n)
/__
n=1

Solution:
We use the limit comparison test with an= [e^(1/n)]/n and bn= 1/n

to obtain lim n-->infinity an/bn.....

Are these the correct values for an and bn??

Thanks

 

[royhaas]

The general term of the series does not converge to zero.