Limit Exercise 3

DrToddMatthews

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Dec 20, 2005
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This exercise is also a true or false question. I've gotten the correct answer, but I did not use all of the given information. I'm curious to know why this information is given.

If f is continuous at 5 and f(5) equals 2 and f(4) equals 3, then the limit as x approaches 2 of f(4*x^2 - 11) is 2.

I say true because 4*x^2 - 11 = 5 when x approaches 2, and we're told that f(5) = 2.

Why does the author tell us that f(4) equals 3?

:?
 
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