K KoryME New member Joined Jul 15, 2012 Messages 2 Jul 15, 2012 #1 I can't find any help or examples of how to solve this example problem in my book, so I'm not even sure where to begin. Find the limit of the proper integral [(x-1)e^(-x) dx] from 0 to infinity. Thanks in advance!
I can't find any help or examples of how to solve this example problem in my book, so I'm not even sure where to begin. Find the limit of the proper integral [(x-1)e^(-x) dx] from 0 to infinity. Thanks in advance!
mmm4444bot Super Moderator Joined Oct 6, 2005 Messages 10,958 Jul 15, 2012 #2 If it were from 0 to 1, instead, what would you think about the integral?
D Deleted member 4993 Guest Jul 15, 2012 #3 KoryME said: I can't find any help or examples of how to solve this example problem in my book, so I'm not even sure where to begin. Find the limit of the proper integral [(x-1)e^(-x) dx] from 0 to infinity. Thanks in advance! Click to expand... Your question does not make sense to me. Please re-read your post and fix it as needed. And... Please share your work with us, indicating exactly where you are stuck - so that we may know where to begin to help you.
KoryME said: I can't find any help or examples of how to solve this example problem in my book, so I'm not even sure where to begin. Find the limit of the proper integral [(x-1)e^(-x) dx] from 0 to infinity. Thanks in advance! Click to expand... Your question does not make sense to me. Please re-read your post and fix it as needed. And... Please share your work with us, indicating exactly where you are stuck - so that we may know where to begin to help you.
H HallsofIvy Elite Member Joined Jan 27, 2012 Messages 7,760 Jul 17, 2012 #4 Probably the simplest way to integrate \(\displaystyle \int (x- 1)e^{-x}dx\) is by parts, letting u= x- 1 and \(\displaystyle dv= e^{-x}dx\).
Probably the simplest way to integrate \(\displaystyle \int (x- 1)e^{-x}dx\) is by parts, letting u= x- 1 and \(\displaystyle dv= e^{-x}dx\).