Is the expression as follows?LIM 16x^2(4x^2- sqr(16x^4+1) )
x->inf
any ideas??
So would we, especially since we can't help you get un-stuck until we can see what you did that got you stuck in the first place.Id like to see the steps
Is the expression as follows?
. . . . .\(\displaystyle 16x^2\left(4x^2\, -\, \sqrt{16x^4\, +\, 1}\right)\)
If so, then what did you get when you followed the example(s) shown in your book (and maybe also on the board in class) with multiplying by the conjugate to make a fraction where stuff cancels?
So would we, especially since we can't help you get un-stuck until we can see what you did that got you stuck in the first place.![]()
need help with this problem
I know the answer is -2 but Id like to see the steps
LIM 16x^2(4x^2- sqr(16x^4+1) )
x->inf
any ideas??
Hello mark:
This is a tutoring web site; volunteers do not provide immediate step-by-step solutions here. Please be sure to check out the forum guidelines.
When taking a limit of an expression that contains a radical like this, one idea to consider right away is conjugation.
That is, rewrite the given expression in rational form, and then multiply top and bottom by the conjugate of the top.
\(\displaystyle \dfrac{16x^2(4x^2 - \sqrt{16x^4 + 1})}{1} \cdot \dfrac{16x^2(4x^2 + \sqrt{16x^4 + 1})}{16x^2(4x^2 + \sqrt{16x^4 + 1})}\)
After simplifying, you may then divide through by the highest power of x, as normally when dealing with limits at infinity.
If you need more help, please show us what you've done so far.
Cheers :cool:
Hello mark:
This is a tutoring web site; volunteers do not provide immediate step-by-step solutions here. Please be sure to check out the forum guidelines.
When taking a limit of an expression that contains a radical like this, one idea to consider right away is conjugation.
That is, rewrite the given expression in rational form, and then multiply top and bottom by the conjugate of the top.
\(\displaystyle \dfrac{16x^2(4x^2 - \sqrt{16x^4 + 1})}{1} \cdot \dfrac{16x^2(4x^2 + \sqrt{16x^4 + 1})}{16x^2(4x^2 + \sqrt{16x^4 + 1})}\)
After simplifying, you may then divide through by the highest power of x, as normally when dealing with limits at infinity.
If you need more help, please show us what you've done so far.
Cheers :cool:
how do I get my next reply to look all math-like