Limit that tends to infinity of (√x + x) / x

Since \(x\to\infty\) we know that \(x>0\) which allows us to write \(\dfrac{x+\sqrt{x}}{x}=\dfrac{1+\sqrt{\frac{1}{x}}}{1}\).
 
You are in calculus and are having trouble simplifying [math]\dfrac{x + \sqrt{x}}{x}[/math]. It can't be that you don't know what x/x equals so it must be that you do not know what [math]\dfrac{\sqrt{x}}{x}[/math]. This is not good at all.
 
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