limit, x -> 0^+, (1 + sin4x)^(cotx): I've started by taking logs

[calculusIsKillingMe]

Can someone help me with the following limit

lim (1+sin4x)^cotx
x->0<sup>+

this is as far as Ive gotten:
lny=cotx *ln(1+sin4x)</sup>

 

[Ishuda]

Can someone help me with the following limit

lim (1+sin4x)^cotx
x->0<sup>+

this is as far as Ive gotten:
lny=cotx *ln(1+sin4x)</sup>

What is the cot(x)? How does that change the expression [think maybe a 1 times a zero over zero]? Do you know about L'Hospital's Rule?

 

[Steven G]

Can someone help me with the following limit

lim (1+sin4x)^cotx
x->0<sup>+

this is as far as Ive gotten:
lny=cotx *ln(1+sin4x)</sup>

So now take the limit as x->0+ of both sides. Also Calculus is not killing you as the calculus part of calculus is not that bad. What may be killing you is algebra, trigonometry and precalculus as calculus requires you to have a strong command of these subjects.
Good luck