S sail0r New member Joined Oct 26, 2008 Messages 12 Dec 10, 2008 #1 Two short limits questions here. I am just not seeing where to go with them. lim x-> 0 (x+3x[sup:1vp0im9d]2[/sup:1vp0im9d])/4x & lim x->2 (x[sup:1vp0im9d]2[/sup:1vp0im9d]-4x+4)/(x[sup:1vp0im9d]3[/sup:1vp0im9d]-4x)
Two short limits questions here. I am just not seeing where to go with them. lim x-> 0 (x+3x[sup:1vp0im9d]2[/sup:1vp0im9d])/4x & lim x->2 (x[sup:1vp0im9d]2[/sup:1vp0im9d]-4x+4)/(x[sup:1vp0im9d]3[/sup:1vp0im9d]-4x)
G galactus Super Moderator Staff member Joined Sep 28, 2005 Messages 7,203 Dec 10, 2008 #2 Re: Limits! Do a little factoring and simplify. They are easy if you do that.
G galactus Super Moderator Staff member Joined Sep 28, 2005 Messages 7,203 Dec 10, 2008 #3 Re: Limits! Factor an x out of the denominator. It is not a difference of cubes. 4x is not a cube. The numerator is a perfect square.
Re: Limits! Factor an x out of the denominator. It is not a difference of cubes. 4x is not a cube. The numerator is a perfect square.
