X xc630 Junior Member Joined Sep 1, 2005 Messages 164 Mar 15, 2006 #1 Hello I need to find the given limit in this problem lim sec (1/n) Under lim is: n arrow infinity How would I go about doin this? I was told I could use a graphing caluclator but I don't know how.
Hello I need to find the given limit in this problem lim sec (1/n) Under lim is: n arrow infinity How would I go about doin this? I was told I could use a graphing caluclator but I don't know how.
S soroban Elite Member Joined Jan 28, 2005 Messages 5,584 Mar 15, 2006 #2 Hello, xc630! You can solve this with basic trig . . . \(\displaystyle \lim_{n\to\infty}\sec\left(\frac{1}{n}\right)\) Click to expand... As \(\displaystyle n\to\infty,\;\frac{1}{n}\to 0\) What is \(\displaystyle \sec(0)\) ?
Hello, xc630! You can solve this with basic trig . . . \(\displaystyle \lim_{n\to\infty}\sec\left(\frac{1}{n}\right)\) Click to expand... As \(\displaystyle n\to\infty,\;\frac{1}{n}\to 0\) What is \(\displaystyle \sec(0)\) ?
X xc630 Junior Member Joined Sep 1, 2005 Messages 164 Mar 15, 2006 #3 Thank you soroban. I believe it is one.
