linear equation word problem

Karrie1113

New member
Joined
Aug 26, 2010
Messages
7
ten times the smallest of 3 consecutive integers is 213 more than the sum of the other two integers. find the integers

here are my thoughts
I=1st integer
I+1=2nd integer
I+2=3rd integer
10(I)=I+1+I+2+213
I think this is the answer but should I go futher?
 
Karrie1113 said:
ten times the smallest of 3 consecutive integers is 213 more than the sum of the other two integers. find the integers

I=1st integer

I+1=2nd integer

I+2=3rd integer

10(I) = I + 1 + I + 2 + 213 ? This is good.

I think this is the answer What ? !

The instruction to "find the integers" means that the question is "What are the three Integers?"

How can the equation above be the answer to that question?

You need to solve your equation for I.

Then, you will know the first Integer.

The next two Integers easily follow.

 
Top