Karrie1113
New member
- Joined
- Aug 26, 2010
- Messages
- 7
ten times the smallest of 3 consecutive integers is 213 more than the sum of the other two integers. find the integers
here are my thoughts
I=1st integer
I+1=2nd integer
I+2=3rd integer
10(I)=I+1+I+2+213
I think this is the answer but should I go futher?
here are my thoughts
I=1st integer
I+1=2nd integer
I+2=3rd integer
10(I)=I+1+I+2+213
I think this is the answer but should I go futher?