Linkage system equation...

CSK225

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Joined
Mar 14, 2008
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Hello,

I'm new here! Please forgive me if I've posted this in the wrong category. I'm not sure exactly where this should be other than this one.

I have a question that's been driving me nuts for quite some time. I have posted a diagram showing a linkage with limited movement. Looking at the diagram, I need to figure out the angle of "Part 2" and "Part 3" for any given distance between 656.258199 and 1110.

Here's the problem:

"Part 1" can ONLY move up and down and the green pivot point at side b and c of "Part 3" can ONLY move up and down. It cannot move back and forth. The red vertical line can be considered a piston that is connected at the pivot point of sides b and c of "Part 3" and extends up inside "Part 1".

The very bottom line in the diagram can be considered a ground line.

The first frame of the illustration shows the linkage at full extension and the second shows the linkage at full compression. "Part 2" starts at sweep angle 0 and at full compression sits at 11.49746749 degrees through an arc of radius = 400.

Side "a" of "Part 3" sits @ 50.75456535 degrees and at full compression is decreased exactly 34 degrees for a resultant angle of 16.75456535 degrees.

I can figure every thing else out if I take an arbitrary sweep angle between 0 and 34 for "Part 3". The problem I have is taking ONLY the vertical distance traveled by "Part 1" and extrapolating the rest from that. I've come very, very close. I just can't seem to figure out the formula though. I know it's possible. Please help me, I'm going crazy. I think I've gone through half a ream of paper working on this and for some reason I'm missing it.

Sincerely,

Cliff
 

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