logarithims

[marlo03]

Solve. Where appropriate, include approximations to the nearest thousandth. If no solution exists, state this.

log[5] (5x - 1) = 1

 

[Mrspi]

Solve. Where appropriate, include approximations to the nearest thousandth. If no solution exists, state this.

log[5] (5x - 1) = 1

Here's a definition which might help you:

log[sub:2n63nyhx]b[/sub:2n63nyhx] n = a MEANS this:

b[sup:2n63nyhx]a[/sup:2n63nyhx] = n

Now, see what that gives you when you apply it to YOUR problem:

log[sub:2n63nyhx]5[/sub:2n63nyhx] (5x - 1) = 1

5[sup:2n63nyhx]1[/sup:2n63nyhx] = (5x - 1)

Does that give you an equation you can solve for x? And does the value you get for x CHECK?

 

[marlo03]

Yes, thank you so very very much!!!