Logarithmic Differentiation

Jason76

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Logarithmic Differentiation:

\(\displaystyle y = x^{\sqrt{x}}\)

\(\displaystyle y = x^{x^{1/2}}\)

\(\displaystyle \ln(y) = \ln(x^{x^{1/2}})\)

\(\displaystyle \ln(y) = x^{1/2}\ln x\)

\(\displaystyle \dfrac{1}{y}y' = \dfrac{1}{2}x^{-1/2}\dfrac{1}{x}\)

\(\displaystyle y' = (y) \dfrac{1}{2}x^{-1/2}\dfrac{1}{x}\)

\(\displaystyle y' = (x^{\sqrt{x}}) \dfrac{1}{2}x^{-1/2}\dfrac{1}{x}\) :confused: Is this right, or on the right track?
 
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Logarithmic Differentiation:

\(\displaystyle y = x^{\sqrt{x}}\)

\(\displaystyle y = x^{x^{1/2}}\)

\(\displaystyle \ln(y) = \ln(x^{x^{1/2}})\)

\(\displaystyle \ln(y) = x^{1/2}\ln x\)

\(\displaystyle \dfrac{1}{y}y' = \dfrac{1}{2}x^{-1/2}\dfrac{1}{x}\)
Shouldn't the Product Rule spit out two terms for the derivative? ;)
 
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