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LOGARITHMS ( HELP )
- Thread starter JOSH BAR
- Start date
As written "7(1.08^3x + 1) = 14" actually means \(\displaystyle 7(1.08^3 x + 1) = 14\).
I think you mean 7(1.08^(3x) + 1) = 14 which means \(\displaystyle 7(1.08^{3x} + 1) = 14\).
Or do you mean 7(1.08^(3x + 1)) = 14 which means \(\displaystyle 7(1.08^{3x + 1}) = 14\)?
To be more specific you need to use parenthesis. Why don't you show us your work so we can see where you went wrong?
I think you mean 7(1.08^(3x) + 1) = 14 which means \(\displaystyle 7(1.08^{3x} + 1) = 14\).
Or do you mean 7(1.08^(3x + 1)) = 14 which means \(\displaystyle 7(1.08^{3x + 1}) = 14\)?
To be more specific you need to use parenthesis. Why don't you show us your work so we can see where you went wrong?
BigGlenntheHeavy
Senior Member
- Joined
- Mar 8, 2009
- Messages
- 1,577
\(\displaystyle 7(1.08^{3x}+1) \ = \ 14\)
\(\displaystyle By \ inspection \ it \ should \ be \ obvious \ that \ x \ = \ 0.\)
\(\displaystyle By \ inspection \ it \ should \ be \ obvious \ that \ x \ = \ 0.\)
BigGlenntheHeavy said:\(\displaystyle 7(1.08^{3x}+1) \ = \ 14\)
\(\displaystyle By \ inspection \ it \ should \ be \ obvious \ that \ x \ = \ 0.\)
Its actually not that problem, it is the 3rd on listed.
7(1.08^(3x+1))=14