Is the first them \(\displaystyle \ln(c^{-1})\) is it \(\displaystyle [\ln(c)]^{-1}\)Can anyone explain to me why I keep getting this wrong? I have 2 answers here and it says they're both wrong...
Ln(a)=2
Ln(b)=3
Ln(c)=5
Ln(c^-1)Is the first them \(\displaystyle \ln(c^{-1})\) is it \(\displaystyle [\ln(c)]^{-1}\)
Assuming that I have read your grouping correctly, here is my take.Can anyone explain to me why I keep getting this wrong? I have 2 answers here and it says they're both wrong...
Ln(a)=2
Ln(b)=3
Ln(c)=5
Jomo, which posting are you answering? It would be most helpful if we all quoted the posts to which we are responding.If you take away 4 cookies and then you take away 6 cookies, THEN you took away 10 cookies. That is -4 - 6 = -10 so -4 + 6 can't be -10!! After all if you took away 4 cookies and put back 6 cookies (so -4 + 6) there are two more cookies then you started with, ie -4+6=2
Post number 1 where the OP was not sure what -4+6 equals.Jomo, which posting are you answering? It would be most helpful if we all quoted the posts to which we are responding.
I got -10 because i multiplied -5(2)...If you take away 4 cookies and then you take away 6 cookies, THEN you took away 10 cookies. That is -4 - 6 = -10 so -4 + 6 can't be -10!! After all if you took away 4 cookies and put back 6 cookies (so -4 + 6) there are two more cookies then you started with, ie -4+6=2
Im not sure why it has the 1 there but thats what the problem says in my assignment. Im just going by what it said... its probably just to throw me off. Anyway, thank you!The part that makes me curious is [MATH]\frac{a}{b^1}[/MATH]. Why would the 1 be written?
But have you considered my comment yet? You changed [MATH]\left(\ln\frac{a}{b^1}\right)^{-2}[/MATH] to [MATH]\ln\left(a^{-2}\right) - \ln\left(b^{2}\right)[/MATH], which is wrong.
I'd just simplify inside the parentheses, then do your substitutions with the given ln values.
Not true, sorry. You had two solutions (remember?) one went as follows: -5(-4+6) = (-5)(2) = -10 and the other solution you had came from -5(-4+6) = (-5)(10) = -50. So you had two results for -4+6. You had 2 and 10!I got -10 because i multiplied -5(2)...
I'm sorry, are you trying to attack me when I was simply asking for help on a math problem? I know what I wrote and posted but that wasn't the end of me trying to solve the problem. If you're going to be ugly about a learning opportunity for me, then please refrain from commenting.Not true, sorry. You had two solutions (remember?) one went as follows: -5(-4+6) = (-5)(2) = -10 and the other solution you had came from -5(-4+6) = (-5)(10) = -50. So you had two results for -4+6. You had 2 and 10!
I'm sorry that you think I was being a jerk. That was not my intention.I'm sorry, are you trying to attack me when I was simply asking for help on a math problem? I know what I wrote and posted but that wasn't the end of me trying to solve the problem. If you're going to be ugly about a learning opportunity for me, then please refrain from commenting.
To clear up what I wrote, it was originally (-5)(-4-6)=(-5)(-10)=50 then I crossed out the (-) and changed it to (+). Which is why it then said (-5)(-4+6)=(-5)(2)=-10. Hence why I had 2 different answers. So now that we have the simpler math out of the way, if you wish to comment more, why don't you add something useful instead of being a jerk?