M is the average value of f(x)=2x^(2) on [0,2]. Find value c such that f(c) = M

[on3winyoureyes]

M is the average value of f(x)=2x^(2) on [0,2]. Find value c such that f(c) = M

I'm not sure how to do this problem. Do we have to find integral from 0 to 2 of 2x^(2). Then we'd get (2/3)x^(3)+C and then multiply it by 1/2 for the average? I'm not sure about the f(c)=M part

 

[pka]

M is the average value of f(x)=2x^(2) on [0,2]. Find value c such that f(c) = M
I'm not sure how to do this problem. Do we have to find integral from 0 to 2 of 2x^(2). Then we'd get (2/3)x^(3)+C and then multiply it by 1/2 for the average? I'm not sure about the f(c)=M part

This is basic, basic algebra: $\displaystyle 2c^2=M~?$

 

[stapel]

M is the average value of f(x)=2x^(2) on [0,2]. Find value c such that f(c) = M

I'm not sure how to do this problem. Do we have to find integral from 0 to 2 of 2x^(2). Then we'd get (2/3)x^(3)+C and then multiply it by 1/2 for the average? I'm not sure about the f(c)=M part

For a worked example expanding on the previous reply, try the bottom of page 2 here.