making a chest piece

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faelicon

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May 23, 2013
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Thank you for taking a moment to help me out.
I have made a lamellar chest peice using 3.5 x 2.5 lame.
It took 160 lames to complete.
Now the lames I would like to use, from a different supplier,
are 2.5 x 1.5 how many will I need to order?
 
faelicon said:
Thank you for taking a moment to help me out.
I have made a lamellar chest peice using 3.5 x 2.5 lame.
It took 160 lames to complete.
Now the lames I would like to use, from a different supplier,
are 2.5 x 1.5 how many will I need to order?
Click to expand...
The surface area of the chest =(3.5∗2.5)∗160=8.75∗160=1400.\displaystyle = (3.5 * 2.5) * 160 = 8.75 * 160 = 1400. Follow me so far?

The surface area of each new lame =2.5∗1.5=3.75.\displaystyle = 2.5 * 1.5 = 3.75. Still with me?

So the minimum number of new lames needed ≥⌈14003.75⌉=374.\displaystyle \ge \lceil\frac{1400}{3.75}\rceil = 374.

The reason that I say minimum is that you may not be able to do this at all. You really need the surface area of each face of the chest. And there may not be a whole number of the new lames that will fit on each face. I do not know whether you can effectively cut down a lame so that they will fit.
 
Denis said:
Confirming: 8.75 / 3.75 * 160 = 373 1/3

Jeff, you're over 2/3 :???:
Click to expand...
I am assuming that you cannot order fractional pieces, which is why I used the ceiling function, but it is not very visible. The whole fractional thing is worrisome. I have no idea what a lame is and whether it can be divided into fractions readily. And the calculations need to be done for each face that has lames.

I may be wrong. If so, I'll come visit you in the corner.
 
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