C cmierau New member Joined Sep 26, 2006 Messages 1 Sep 26, 2006 #1 . . . . . . . . .(t/n) if y = A x 2 where (t/n) is the exponent of 2 and A is a constant, SOLVE for t when given both A and y data . . . . . . . . . . . . . . . . . (t/n) I get as far as y/A = 2 so basically, what is the inverse of a power?
. . . . . . . . .(t/n) if y = A x 2 where (t/n) is the exponent of 2 and A is a constant, SOLVE for t when given both A and y data . . . . . . . . . . . . . . . . . (t/n) I get as far as y/A = 2 so basically, what is the inverse of a power?
tkhunny Moderator Staff member Joined Apr 12, 2005 Messages 11,325 Sep 26, 2006 #2 You'll need a logarithm.
D Denis Senior Member Joined Feb 17, 2004 Messages 1,700 Sep 26, 2006 #3 cmierau said: . . . . . . . . .(t/n) if y = A x 2 Click to expand... Please do not use "x" for multiplication; looks like a variable: use * And post like this: y = A * 2^(t/n) ; ^ means "to the power" 2^(t/n) = y / A t/n = log(y / A) / log(2) Finish it.
cmierau said: . . . . . . . . .(t/n) if y = A x 2 Click to expand... Please do not use "x" for multiplication; looks like a variable: use * And post like this: y = A * 2^(t/n) ; ^ means "to the power" 2^(t/n) = y / A t/n = log(y / A) / log(2) Finish it.
