manipulate a formula to solve for an exponent

[cmierau]

. . . . . . . . .(t/n)
if y = A x 2


where (t/n) is the exponent of 2 and A is a constant,

SOLVE for t when given both A and y data

. . . . . . . . . . . . . . . . . (t/n)
I get as far as y/A = 2


so basically, what is the inverse of a power?

 

[tkhunny]

You'll need a logarithm.

 

[Denis]

. . . . . . . . .(t/n)
if y = A x 2

Please do not use "x" for multiplication; looks like a variable: use *
And post like this:
y = A * 2^(t/n) ; ^ means "to the power"

2^(t/n) = y / A
t/n = log(y / A) / log(2)

Finish it.