Math 131

[sonrays06]

If a quantity is growing as a linear function with a constant rate of change of m per year, how do you use this year's amount to find next year's amount?

 

[tkhunny]

Linear functions do not grow at a constant RATE. Exponential functions do.
Linear functions grow by a constant AMOUNT. Try adding m.

 

[sonrays06]

Linear functions do not grow at a constant RATE. Exponential functions do.
Linear functions grow by a constant AMOUNT. Try adding m.

a. This year's amount divided by m.
b. This year's amount plus m.
c. This year's amount plus 2m.
d. This year's amount minus m.
e. This year's amount times m.

 

[Dr.Peterson]

Linear functions do not grow at a constant RATE. Exponential functions do.
Linear functions grow by a constant AMOUNT. Try adding m.

I would say that linear functions do have a constant rate of change (also called the slope).

But the point is still true: You are told that it increases by m each year; so next year it will be m more than this year.

 

[Steven G]

This is not a free math homework service site. It is a free math help site where we help students solve their problems. So please share with us what you have done and where you are stuck so that we can guide you to the solution.

 

[HallsofIvy]

a. This year's amount divided by m.
b. This year's amount plus m.
c. This year's amount plus 2m.
d. This year's amount minus m.
e. This year's amount times m.

Is the correct answer to be chosen from these? Why didn't you say so in your first post? Any way, which were you told, by tkhunny is correct?