MATH PROBLEM(7)

emmaiskool242 said:
m^2 m +n
__________ X _________

8m^2-8n^2 m^3 + m^2

Please re-type in CLEAR fashion...see my previous post to you...
 
Hello, emmaiskool242!

Don't you ever LOOK at what you posted?
Haven't you caught on that your formatting is NOT preserved
\(\displaystyle \;\;\)and no one can read your problems?
And in algebra, we do NOT use "X" for multiplication!

m^2 m +n
__________ X _________

8m^2-8n^2 m^3 + m^2
We can only GUESS at what you meant . . .

I assume the problem is: \(\displaystyle \L\:\frac{m^2}{8m^2\,-\,8n^2}\,\cdot\,\frac{m\,+\,n}{m^3\,+\,m^2}\)

Okay, one more time . . . FACTOR everything as much as possible.

And we have: \(\displaystyle \L\:\frac{m^2}{8(m\,-\,n)(m\,+\,n)}\,\cdot\frac{m\,+\,n}{m^2(m\,+\,1)}\)


Then reduce (cancel) as much as possible:

\(\displaystyle \L\:\frac{\sout{m^2}}{8(m\,-\,n)(\sout{m\,+\,n})}\,\cdot\frac{\sout{m\,+\,n}}{\sout{m^2}(m\,+\,1)} \;= \;\frac{1}{8(m\,-\,n)(m\,+\,1)}\)


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Don't try to make a "picture" of your problems.
They can be written "horizontally" like this:

(m^2)/(8m^2 - 8n^2) times (m + n)/(m^3 + m^2)

Enclose the numerators and denominators in parentheses

Otherwise, you'll see something like : x - 2/y + y + 1/x - 3 \(\displaystyle \;\) *
. . . and who knows what the fractions are?

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*
Or worse: \(\displaystyle \;\)x-2/y+y+1/x-3

How come NO ONE uses spaces?

If your teacher wrote an exam problem like this: x+3/x-4+x-3/x+4
\(\displaystyle \;\;\)and you got it wrong, you'd complain . . . loudly.

IthinkI'llstartansweringquestionslikethis.
 
soroban..thanks for the help and next time I will check my work,and use a * instead of an X(i knew that that you could use *).I will try writing my problem in a different format instead of painting a picture. THANKS AGAIN~emmaiskool242
 
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