Hello, emmaiskool242!
I think I figured out what you're saying . . .
I'm using the distance formula: \(\displaystyle \,D\:=\:\sqrt{(x_2-x_1)^2\,+\,(y_2-y_1)^2}\)
I am supposed to plug in the points \(\displaystyle \left(3,\,\frac{3}{7}\right)\) and \(\displaystyle \left(4,-\frac{2}{7}\right)\)
and I'm supposed to figure out what \(\displaystyle D\) equals.
Exactly
where is your difficulty?
\(\displaystyle \;\;\)You don't understand where the numbers go?
\(\displaystyle \;\;\)You can't handle fractions?
\(\displaystyle \;\;\)A square root gives you brain-freeze?
Try to "read" the Distance Formula.
Under the square root, it says:
\(\displaystyle \;\;\)Subtract the two x-values ... and square.
\(\displaystyle \;\;\)Subtract the two y-values ... and square.
\(\displaystyle \;\;\)Add the two quantities
\(\displaystyle \;\;\)Take the square root.
We have: \(\displaystyle \
\:=\:\sqrt{(4 - 3)^2\,+\,\left(-\frac{2}{7}\,-\,\frac{3}{7}\right)^2} \:= \:\sqrt{1^2\,+\,\left(-\frac{5}{7}\right)^2}\:=\:\sqrt{1\,+\,\frac{25}{49}} \:=\:\sqrt{\frac{74}{49}}\)
Therefore: \(\displaystyle \,D\:=\:\frac{\sqrt{74}}{\sqrt{49}}\:=\:\frac{\sqrt{74}}{7}\)