math trouble Compound inequalites

[#horrible@math]

14)

 

[tkhunny]

#1 Get a new screen name. Why would you ever succeed with an attitude like that?

#2 What happens when you deal with the inequalities separately?

 

[pka]

14)	View attachment 21993

Because mathematics set theory lets rewrite this as \(A=\{x: 3+3x<2+2x\}~\&~B=\{x: 5x-5\ge 5-5x\}\)
So we are looking for the set \(A\cup B\). But \(A=\{x: x<-1\}~\&~B=\{x: x\ge 1\}\) Do you agree?
What is \(A\cup B=~?\)