B bearej50 New member Joined Feb 16, 2009 Messages 21 Feb 16, 2009 #1 Prove by induction that, for all natural numbers, if 0 < x < y, then x^n < y^n. I know it seems simple but I am having trouble making it make sense
Prove by induction that, for all natural numbers, if 0 < x < y, then x^n < y^n. I know it seems simple but I am having trouble making it make sense
R royhaas Full Member Joined Dec 14, 2005 Messages 832 Feb 16, 2009 #2 For the induction step, multiply by \(\displaystyle x\).
