May someone please explain what should be done here

CHiMER4

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A curve is such that
dy/dx= (√x/2) + (5/x^2)

Use an indefinite integral to find the equation of this curve, given that the point (1;10) lies on the curve.
 

Subhotosh Khan

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A curve is such that
dy/dx= (√x/2) + (5/x^2)

Use an indefinite integral to find the equation of this curve, given that the point (1;10) lies on the curve.
Please show us what you have tried and exactly where you are stuck.

Please follow the rules of posting in this forum, as enunciated at:


Please share your work/thoughts about this problem.
 

Dr.Peterson

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A curve is such that
dy/dx= (√x/2) + (5/x^2)

Use an indefinite integral to find the equation of this curve, given that the point (1;10) lies on the curve.
They've told you what to do: integrate both sides with respect to x. Then you'll be determining the value of the constant from the given point.
 

CHiMER4

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Okay

I got to
y=(x^(3/2)/3) + 5/x + c
When x= 1, y=10
10=(1^(3/2)/3) +5/1 +c
c=14/3

Therefore equation is
y= (x^(3/2)/3)+5/x+14/3
 

Dr.Peterson

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I got to
y=(x^(3/2)/3) + 5/x + c
When x= 1, y=10
10=(1^(3/2)/3) +5/1 +c
c=14/3

Therefore equation is
y= (x^(3/2)/3)+5/x+14/3
That's mostly good; just check a sign and fix the subsequent work.

It would have been a good idea to check your answer by taking its derivative.
 
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