# May someone please explain what should be done here

#### CHiMER4

##### New member
A curve is such that
dy/dx= (√x/2) + (5/x^2)

Use an indefinite integral to find the equation of this curve, given that the point (1;10) lies on the curve.

#### Subhotosh Khan

##### Super Moderator
Staff member
A curve is such that
dy/dx= (√x/2) + (5/x^2)

Use an indefinite integral to find the equation of this curve, given that the point (1;10) lies on the curve.
Please show us what you have tried and exactly where you are stuck.

Please follow the rules of posting in this forum, as enunciated at:

#### Dr.Peterson

##### Elite Member
A curve is such that
dy/dx= (√x/2) + (5/x^2)

Use an indefinite integral to find the equation of this curve, given that the point (1;10) lies on the curve.
They've told you what to do: integrate both sides with respect to x. Then you'll be determining the value of the constant from the given point.

#### CHiMER4

##### New member
Okay

I got to
y=(x^(3/2)/3) + 5/x + c
When x= 1, y=10
10=(1^(3/2)/3) +5/1 +c
c=14/3

Therefore equation is
y= (x^(3/2)/3)+5/x+14/3

#### Dr.Peterson

##### Elite Member
I got to
y=(x^(3/2)/3) + 5/x + c
When x= 1, y=10
10=(1^(3/2)/3) +5/1 +c
c=14/3

Therefore equation is
y= (x^(3/2)/3)+5/x+14/3
That's mostly good; just check a sign and fix the subsequent work.

It would have been a good idea to check your answer by taking its derivative.

#### CHiMER4

##### New member
That's mostly good; just check a sign and fix the subsequent work.

It would have been a good idea to check your answer by taking its derivative.
Oh, thank you for your time