Hello! Can anybody help me with this question?
The function f(x)=x^2 assumes the value of its integral average over the integral [0,3].
a)at point x0=sqrt(3)
b)at point x0=sqrt(5)/2
c)at point x0=sqrt(3)/3
d)at point x0=3/2
e) never on the given interval
I would say 3 with the formula for mean value theorem for integration but I don't see 3 in the answers. What am I doing wrong?
The function f(x)=x^2 assumes the value of its integral average over the integral [0,3].
a)at point x0=sqrt(3)
b)at point x0=sqrt(5)/2
c)at point x0=sqrt(3)/3
d)at point x0=3/2
e) never on the given interval
I would say 3 with the formula for mean value theorem for integration but I don't see 3 in the answers. What am I doing wrong?
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