Might be a stupid question....

[calculusdunce]

So I can't seem to get this to come out correctly.

I'm a little fried, so I am probably asking a stupid question or making a stupid mistake.



I found g. Or at least, I thought I did.

[MATH]\int g=f[/MATH]
[MATH]\int g=sin(x)[/MATH]
[MATH]\int cos(x)=sin(x) +C[/MATH]
Derivative of [MATH]cos(x)=-sin(x)[/MATH]
[MATH]-sin(\pi/2)=-1[/MATH]
The online grader says -1 isn't right. What did I do wrong?

 

[Dr.Peterson]

Another way to say it is that g is the derivative of f, so g' is the second derivative of f. Since f(x) = sin(x), f'(x) = cos(x) and f''(x) = -sin(x). Therefore `g'(pi/2) = -sin(pi/2) = -1`.

I agree with you.

Can you show us any more of the problem, such as how you were to enter the answer?

And what does `9_{59}` mean?

 

[calculusdunce]

Just to update:

I was a dufus and didn't enter the problem right as a result of a tecnicality, but the professor reset it for me when I asked him about it, so we're all good.

Just living up to my username, everybody.