L lalala84 New member Joined Nov 18, 2006 Messages 5 Dec 15, 2006 #1 hi, how do i go from this line: 1/(-2y^2) = (x^3 + C)/3 to: (-2y^2) = 3/(x^3 + C) it's more than just "flipping" each side, right? what's the technical way of saying/doing it? Thanks
hi, how do i go from this line: 1/(-2y^2) = (x^3 + C)/3 to: (-2y^2) = 3/(x^3 + C) it's more than just "flipping" each side, right? what's the technical way of saying/doing it? Thanks
stapel Super Moderator Staff member Joined Feb 4, 2004 Messages 16,550 Dec 15, 2006 #2 lalala84 said: it's more than just "flipping" each side, right? Click to expand... I don't think so. I suppose one could think of it as cross-multiplying, followed by "cross-dividing", maybe.... lalala84 said: what's the technical way of saying/doing it? Click to expand... "Inverting both sides"...? "Taking the reciprocals"...? Eliz.
lalala84 said: it's more than just "flipping" each side, right? Click to expand... I don't think so. I suppose one could think of it as cross-multiplying, followed by "cross-dividing", maybe.... lalala84 said: what's the technical way of saying/doing it? Click to expand... "Inverting both sides"...? "Taking the reciprocals"...? Eliz.
