I have two problems I need to complete for my discrete structures class. I've finished all the rest except these two. Can anyone help me out? I'm a CIS student and don't have an extremly strong backgroun in math.
I do not know where to start with this one:
There exist, for each element s in Z, unique elements u in Z and μn(s) in Zn such that s=nu+μn(s) Thus,
μn:Z→Zn,z↦μn(z)
is a map from Z to Zn. This map is called a mod function for n.
Write down all the values of the map
σ:Z15→Z3×Z5,r→(μ3(r),μ5(r))
(thereby showing that σ is bijective.
Any help is really appreciated!
JJ
Someone has told me this but im trying to still figure it out:
would
6→(0,1)
5→(1,4)
4→(3,1)
be elements also? Im trying to figure out how he got those elements and how to get the rest
I do not know where to start with this one:
There exist, for each element s in Z, unique elements u in Z and μn(s) in Zn such that s=nu+μn(s) Thus,
μn:Z→Zn,z↦μn(z)
is a map from Z to Zn. This map is called a mod function for n.
Write down all the values of the map
σ:Z15→Z3×Z5,r→(μ3(r),μ5(r))
(thereby showing that σ is bijective.
Any help is really appreciated!
JJ
Someone has told me this but im trying to still figure it out:
simonstrong said:Each element of the map σ has the form
a→(b,c)
where a is a member of Z15, b is a member of Z3 and c is a member of Z5.
For example, if μ15(n)=7 (i.e. n=7 mod 15), then μ3(n)=1 and μ5(n)=2, so one element of σ is:
7→(1,2)
Go through all 15 members of Z15 and show that each one maps to a different member of Z3×Z5.
would
6→(0,1)
5→(1,4)
4→(3,1)
be elements also? Im trying to figure out how he got those elements and how to get the rest