more limit woes

[spezialize]

if limit as x->2 F(x)=5 and limit x->2 g(x) = -2 find limit as x->2 (2f(x)-g(x))

I have no clue where to start with this problem,

 

[stapel]

How is F(x) related to f(x) and g(x)?

In any case, you should have been taught that limits are additive when they exist, so you can just plug-n-chug.

Eliz.

HMC Tutorial: Computing Limits
Limit Properties

 

[spezialize]

sorry F is suppose to be f

 

[pka]

The answer is 12.
But you need to be able to explain WHY.
So tell us why that is the answer.

 

[stapel]

And if you don't know "why", click the links (provided earlier) and review those online lessons, where this topic is discussed.

Eliz.

 

[spezialize]

so if i plug in (2*5)-(-2) then the limit is 12.. so lim as X->2 = 12... because the limits of f and g are approaching 2 as well?