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Tinkermom

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Sep 17, 2010
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Ok. going to tackle LHS. I change everything on LHS to sine and cosine.

cos? (tan? + cot?)=csc?
= cos? (sin?/cos?) + cos?(cos?/sin?)
= sin? + cos^2?/sin?
= 1 + (cos^2?)/sin?
= (1 + 1-cos^2?)/sin?
= (1+ 1-sin^2?)/sin?

I don't know what to do next...
 
Tinkermom said:
Ok. going to tackle LHS. I change everything on LHS to sine and cosine.

cos? (tan? + cot?)=csc?
= cos? (sin?/cos?) + cos?(cos?/sin?)
= sin? + cos^2?/sin?
= 1 + (cos^2?)/sin?
= (1 + 1-cos^2?)/sin?
= (1+ 1-sin^2?)/sin?

I don't know what to do next...

You maybe need some grouping symbols in this step:

I am going to use "x" instead of theta.....


= cos x( sin x / cos x) + cos x(cos x / sin x)

= (sin x) + (cos[sup:1tus4cy4]2[/sup:1tus4cy4] x / sin x)

or,

= (sin x / 1) + (cos[sup:1tus4cy4]2[/sup:1tus4cy4] x / sin x)

If you want to combine those fractions, you need a common denominator, which is sin x.....

= (sin x / 1)*(sin x / sin x) + (cos[sup:1tus4cy4]2[/sup:1tus4cy4] x / sin x)

= (sin[sup:1tus4cy4]2[/sup:1tus4cy4] x / sin x) + (cos[sup:1tus4cy4]2[/sup:1tus4cy4] x / sin x)

The denominators are now the same. ADD the numerators, and put the result over the common denominator:

= (sin[sup:1tus4cy4]2[/sup:1tus4cy4] x + cos[sup:1tus4cy4]2[/sup:1tus4cy4] x) / sin x

Can you finish it now? Hint: what can you substitute for (sin[sup:1tus4cy4]2[/sup:1tus4cy4] x + cos[sup:1tus4cy4]2[/sup:1tus4cy4] x)?
 
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