Moved - chain rule, product rule,

[kss]

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If you could answer a couple more questions I would really appreciate your help.

1. Find the equation of the tangent line to the curve g(x) = [(x+2)(x^2+x)]/[x-4] at (1,-2)

I know I'm supposed to find g'(x) and that is the slope and I just plug it in to find the equation.
What I can't figure out is do I just FOIL the top and then use the quotient rule or do I do the product rule on top then use quotient rule?

 

[lookagain]

Okay so that make a little sense now. I was on the right direction but just needed some clarification.

If you could answer a couple more questions I would really appreciate your help.

1. Find the equation of the tangent line to the curve g(x) = [(x+2)(x^2+x)]/[x-4] at (1,-2)

I know I'm supposed to find g'(x) and that is the slope and I just plug it in to find the equation.
What I can't figure out is do I just FOIL the top and then use the quotient rule or do I do the product rule on top then use quotient rule?

2. Find the second derivative of d(t) = t/(t^2+3)

I found the first derivative which is [-t^2+3]/[(t^2+3)^2]
The problem I'm having with this question is when I find the second derivative do I use the chain rule while I use the quotient rule?

I can't figure out if it is okay to use more than 1 rule on one function.

Please start new questions in a separate thread. Thank you.

 

[stapel]

1. Find the equation of the tangent line to the curve g(x) = [(x+2)(x^2+x)]/[x-4] at (1,-2)

I know I'm supposed to find g'(x) and that is the slope and I just plug it in to find the equation.
What I can't figure out is do I just FOIL the top and then use the quotient rule or do I do the product rule on top then use quotient rule?

As long as you're careful with your work, the result shouldn't matter. That being said, though, I usually find trying to apply the Product Rule in the middle of applying the Quotient Rule to be a royal pain in the keister. So I would multiply things out in the numerator first. But that's just my personal preference. You should do what works more reliably for you.