J Jade Junior Member Joined Sep 16, 2006 Messages 95 Sep 24, 2006 #1 g(x) = 2x^2 + 3 [g(x + h) - g(x)] / h Would this be: gx + gh - gx/h or: 2x^2 + 3 + h - 2x^2 + 3/h I am having problems computing the top??
g(x) = 2x^2 + 3 [g(x + h) - g(x)] / h Would this be: gx + gh - gx/h or: 2x^2 + 3 + h - 2x^2 + 3/h I am having problems computing the top??
skeeter Elite Member Joined Dec 15, 2005 Messages 3,204 Sep 24, 2006 #2 g(x) = 2x<sup>2</sup> + 3 g(x+h) = 2(x+h)<sup>2</sup> + 3 = 2(x<sup>2</sup> + 2xh + h<sup>2</sup>) + 3 = 2x<sup>2</sup> + 4xh + 2h<sup>2</sup> + 3 now, you tell me ... what is [g(x+h) - g(x)]/h ???
g(x) = 2x<sup>2</sup> + 3 g(x+h) = 2(x+h)<sup>2</sup> + 3 = 2(x<sup>2</sup> + 2xh + h<sup>2</sup>) + 3 = 2x<sup>2</sup> + 4xh + 2h<sup>2</sup> + 3 now, you tell me ... what is [g(x+h) - g(x)]/h ???
J Jade Junior Member Joined Sep 16, 2006 Messages 95 Sep 24, 2006 #3 I got it I need to get into function mode - x+h takes the place of x The answer would be 2x^2=4xh+2h^2+3/h
I got it I need to get into function mode - x+h takes the place of x The answer would be 2x^2=4xh+2h^2+3/h
stapel Super Moderator Staff member Joined Feb 4, 2004 Messages 16,550 Sep 24, 2006 #4 Jade said: I need to get into function mode - x+h takes the place of x Click to expand... So plug "x + h" (without your "minus" sign, above) in for "x" in the formula for "g(x)". Simplify. From this, subtract the formula for "g(x)". Simplify. Divide the result by h. Simplify. There should not be any "equals" sign in your final expression. Eliz.
Jade said: I need to get into function mode - x+h takes the place of x Click to expand... So plug "x + h" (without your "minus" sign, above) in for "x" in the formula for "g(x)". Simplify. From this, subtract the formula for "g(x)". Simplify. Divide the result by h. Simplify. There should not be any "equals" sign in your final expression. Eliz.