J Jade Junior Member Joined Sep 16, 2006 Messages 95 Sep 17, 2006 #1 9x/3x-1+4/3x+1=3 I am having issues with this one. Do you use the Quadratic formula? How do you get this in the 3x^2=4x/3=3 form??????? :?:
9x/3x-1+4/3x+1=3 I am having issues with this one. Do you use the Quadratic formula? How do you get this in the 3x^2=4x/3=3 form??????? :?:
skeeter Elite Member Joined Dec 15, 2005 Messages 3,204 Sep 17, 2006 #2 in future, use correct grouping symbols for clarity's sake ... 9x/(3x-1) + 4/(3x+1) = 3 common denominator is (3x+1)(3x-1) ... 9x(3x+1)/[(3x+1)(3x-1)] + 4(3x-1)/[(3x+1)(3x-1)] = 3 [9x(3x+1) + 4(3x-1)]/[(3x+1)(3x-1)] = 3 9x(3x+1) + 4(3x-1) = 3(3x+1)(3x-1) 27x<sup>2</sup> + 9x + 12x - 4 = 3(9x<sup>2</sup> - 1) 27x<sup>2</sup> + 21x - 4 = 27x<sup>2</sup> - 3 21x - 4 = -3 21x = 1 x = 1/21 what were you saying about the quadratic formula?
in future, use correct grouping symbols for clarity's sake ... 9x/(3x-1) + 4/(3x+1) = 3 common denominator is (3x+1)(3x-1) ... 9x(3x+1)/[(3x+1)(3x-1)] + 4(3x-1)/[(3x+1)(3x-1)] = 3 [9x(3x+1) + 4(3x-1)]/[(3x+1)(3x-1)] = 3 9x(3x+1) + 4(3x-1) = 3(3x+1)(3x-1) 27x<sup>2</sup> + 9x + 12x - 4 = 3(9x<sup>2</sup> - 1) 27x<sup>2</sup> + 21x - 4 = 27x<sup>2</sup> - 3 21x - 4 = -3 21x = 1 x = 1/21 what were you saying about the quadratic formula?
J Jade Junior Member Joined Sep 16, 2006 Messages 95 Sep 18, 2006 #3 :lol: YOU HELPED ME SO MUCH!!!! IT SEEMS MUCH EASIER TO ME NOW!