[MOVED] solve e^x - 12 e^(-x) = -4

[Guest]

How could I solve this equation
e^x - 12*e^-x= -4

 

[pka]

Can you solve \(\displaystyle z^2 + 4z -12 = 0\)?
If you can then \(\displaystyle z = e^x\).

 

[stapel]

e^x - 12*e^-x= -4

One method is to multiply through by e^x and rearranging, yielding e^2x + 4e^x - 12 = 0.

Then solve the quadratic for "e^x=", and apply the natural log to complete the solution.

Eliz.