J josh123 Junior Member Joined Oct 5, 2005 Messages 52 Nov 1, 2005 #1 If f(x) = (x - 2)1/3, then f -1(x) = a. (x^3 + 1)/2 b. (x^3 - 1)/2 c. (x^3 + 2)/2 d. (x^3 - 2)/2 I know this isn't it e. x^3 - 2 f. x^3 + 2 g. none of these Is it either e or f?
If f(x) = (x - 2)1/3, then f -1(x) = a. (x^3 + 1)/2 b. (x^3 - 1)/2 c. (x^3 + 2)/2 d. (x^3 - 2)/2 I know this isn't it e. x^3 - 2 f. x^3 + 2 g. none of these Is it either e or f?
K K New member Joined Nov 1, 2005 Messages 1 Nov 1, 2005 #2 josh123 said: If f(x) = (x - 2)1/3, then f -1(x) = a. (x^3 + 1)/2 b. (x^3 - 1)/2 c. (x^3 + 2)/2 d. (x^3 - 2)/2 I know this isn't it e. x^3 - 2 f. x^3 + 2 g. none of these Is it either e or f? Click to expand... F Here's why: (x - 2)^(1/3) = y x - 2 = y^3 x = y^3 + 2
josh123 said: If f(x) = (x - 2)1/3, then f -1(x) = a. (x^3 + 1)/2 b. (x^3 - 1)/2 c. (x^3 + 2)/2 d. (x^3 - 2)/2 I know this isn't it e. x^3 - 2 f. x^3 + 2 g. none of these Is it either e or f? Click to expand... F Here's why: (x - 2)^(1/3) = y x - 2 = y^3 x = y^3 + 2
