jayjay5531
New member
- Joined
- Nov 23, 2014
- Messages
- 5
I just want to make sure I did this problem right. The problem was: Find ∫∫D (x + y) dV, where D is the rhombus with vertices (0, 0); (5, 0); (5/2, 5/2); and (5/2, −5/2). We were given these formulas to use for change of variables: x = 2u + 3v, and y = 2u − 3v.
After sketching the region and calculating the Jacobian Determinant, I came up with the following integral: −12 ∫5/6∫5/4 4u du dv (the lower limits of integration are supposed to be 0, I didn't know how to format it though). My final answer was −125/4. Somehow this feels wrong?? I guess I didn't expect it to be negative. Did I do something wrong?
After sketching the region and calculating the Jacobian Determinant, I came up with the following integral: −12 ∫5/6∫5/4 4u du dv (the lower limits of integration are supposed to be 0, I didn't know how to format it though). My final answer was −125/4. Somehow this feels wrong?? I guess I didn't expect it to be negative. Did I do something wrong?