n=(30,300)/(1+100e^-.6t) n=30,000

[alexisonfire181]

The number of people infected by a disease in t days ig given by n=(30,300)/(1+100e^-.6t). how many days will it be until 30,000 people are infected.

 

[skeeter]

if \(\displaystyle \L 30000 = \frac{30300}{1+100e^{-.6t}}\)

then \(\displaystyle \L 1 + 100e^{-.6t} = \frac{30300}{30000}\)

solve for t.

 

[alexisonfire181]

im still confused, What is e?

 

[skeeter]

if you have not yet been introduced to the number e, the base number of the natural logarithm, why then are you solving an equation with e in it?