natural log problem: 4.55 = ln(a)+3.19[(4.2-ln(a))/1.6]

[RHal]

Hi,

I'm trying to solve for a and I can't remember how to manipulate logs.

4.55 = ln(a)+3.19[(4.2-ln(a))/1.6]

I just need some direction.

Thanks,

RHal

 

[Deleted member 4993]

Hi,

I'm trying to solve for a and I can't remember how to manipulate logs.

4.55 = ln(a)+3.19[(4.2-ln(a))/1.6]

I just need some direction.

Thanks,

RHal

Replace 'ln(a)' by 'x' in the given equation:

4.55 = ln(a)+3.19[(4.2-ln(a))/1.6]

to get:

4.55 = x + 3.19[(4.2 - x)/1.6]

Now solve for 'x' to get a numerical value for 'x'. What do you get?