need help figuring out x+5/2 + x+2/7 =2
- Thread starter paigep
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As posted, this is a linear equation:paigep said:
. . . . .\(\displaystyle x\, +\, \frac{5}{2}\, +\, x\, +\, \frac{2}{7}\, =\, 2\)
Was this what you meant?
I'm sorry, but I don't understand what you mean by this...? Are you saying that you aren't familiar with the topic (you were out sick those days, or something) and cannot even get started? Or are you saying that you've made what you thought was good progress, but your answer doesn't match the back of the book? Or something else?paigep said:
Please reply with clarification, including showing everything you have tried so far (or else stating that you don't know how to get started, so you need lesson links for study). Thank you!
Eliz.
I am assuming you mean:
\(\displaystyle \frac{x+5}{2}+\frac{x+2}{7}=2\)
What Stapel is tryng to say is to use proper grouping symbols. The way you have it can be construed in various ways.
You could write it as (x+5)/2+(x+2)/7=2. That way we know what you mean. The way you have it you could mean
\(\displaystyle x+\frac{5}{2}+x+\frac{2}{7}=2\). Unless that is what you mean.
Anyway, assuming the former, multiply through by the LCD, which is 14. That will eliminate the fraction and you can proceed.
Okey-doke?.
\(\displaystyle \frac{x+5}{2}+\frac{x+2}{7}=2\)
What Stapel is tryng to say is to use proper grouping symbols. The way you have it can be construed in various ways.
You could write it as (x+5)/2+(x+2)/7=2. That way we know what you mean. The way you have it you could mean
\(\displaystyle x+\frac{5}{2}+x+\frac{2}{7}=2\). Unless that is what you mean.
Anyway, assuming the former, multiply through by the LCD, which is 14. That will eliminate the fraction and you can proceed.
Okey-doke?.