D dongzkie New member Joined Sep 30, 2016 Messages 2 Sep 30, 2016 #1 Hello Guys Need help here on how to transpose this formula, need to get the weight. 0.4501=SQRT{(4 x weight) / (8.89 X 3.14159)} thanks in advance.
Hello Guys Need help here on how to transpose this formula, need to get the weight. 0.4501=SQRT{(4 x weight) / (8.89 X 3.14159)} thanks in advance.
D Deleted member 4993 Guest Oct 2, 2016 #2 dongzkie said: Hello Guys Need help here on how to transpose this formula, need to get the weight. 0.4501=SQRT{(4 x weight) / (8.89 X 3.14159)} thanks in advance. Click to expand... \(\displaystyle \displaystyle{0.4501 \ = \ \sqrt{\dfrac{4 * weight}{8.89 * \pi}}}\) \(\displaystyle \displaystyle{(0.4501)^2 \ = \ \dfrac{4 * weight}{8.89 * \pi}}\) \(\displaystyle \displaystyle{(0.4501)^2 * {8.89 * \pi}\ = \ 4 * weight}\) continue....
dongzkie said: Hello Guys Need help here on how to transpose this formula, need to get the weight. 0.4501=SQRT{(4 x weight) / (8.89 X 3.14159)} thanks in advance. Click to expand... \(\displaystyle \displaystyle{0.4501 \ = \ \sqrt{\dfrac{4 * weight}{8.89 * \pi}}}\) \(\displaystyle \displaystyle{(0.4501)^2 \ = \ \dfrac{4 * weight}{8.89 * \pi}}\) \(\displaystyle \displaystyle{(0.4501)^2 * {8.89 * \pi}\ = \ 4 * weight}\) continue....
D dongzkie New member Joined Sep 30, 2016 Messages 2 Oct 2, 2016 #3 a many thanks Subhotosh Khan said: \(\displaystyle \displaystyle{0.4501 \ = \ \sqrt{\dfrac{4 * weight}{8.89 * \pi}}}\) \(\displaystyle \displaystyle{(0.4501)^2 \ = \ \dfrac{4 * weight}{8.89 * \pi}}\) \(\displaystyle \displaystyle{(0.4501)^2 * {8.89 * \pi}\ = \ 4 * weight}\) continue.... Click to expand...
a many thanks Subhotosh Khan said: \(\displaystyle \displaystyle{0.4501 \ = \ \sqrt{\dfrac{4 * weight}{8.89 * \pi}}}\) \(\displaystyle \displaystyle{(0.4501)^2 \ = \ \dfrac{4 * weight}{8.89 * \pi}}\) \(\displaystyle \displaystyle{(0.4501)^2 * {8.89 * \pi}\ = \ 4 * weight}\) continue.... Click to expand...