J jordan83 New member Joined Nov 9, 2005 Messages 15 Nov 11, 2005 #1 cos(alpha-beta)cos(alpha+beta) = cos^2(alpha) - sin^2(beta) Need to prove them to be equal. Thank you!
cos(alpha-beta)cos(alpha+beta) = cos^2(alpha) - sin^2(beta) Need to prove them to be equal. Thank you!
G Gene Senior Member Joined Oct 8, 2003 Messages 1,904 Nov 11, 2005 #2 a=alpha b=beta cos(a-b)cos(a+b) = sum of angles) cos(-b)=cos(b) sin(-b)=-sin(b) cos(a)cos(b)+sin(a)sin(b) * cos(a)cos(b)-sin(a)sin(b) = (u+v)(u-v)=u<sup>2</sup>-v<sup>2</sup> cos<sup>2</sup>(a)cos<sup>2</sup>(b)-sin<sup>2</sup>(a)sin<sup>2</sup>(b) sin<sup>2</sup>(u)+cos<sup>2</sup>(v) = 1 cos<sup>2</sup>(a)(1-sin<sup>2</sup>(b))-sin<sup>2</sup>(b)(1-cos<sup>2</sup>(a)) = cos<sup>2</sup>(a)-sin<sup>2</sup>(b)cos<sup>2</sup>(a)-sin<sup>2</sup>(b)+cos<sup>2</sup>(a)sin<sup>2</sup>(b) = cos<sup>2</sup>(a)-sin<sup>2</sup>(b)
a=alpha b=beta cos(a-b)cos(a+b) = sum of angles) cos(-b)=cos(b) sin(-b)=-sin(b) cos(a)cos(b)+sin(a)sin(b) * cos(a)cos(b)-sin(a)sin(b) = (u+v)(u-v)=u<sup>2</sup>-v<sup>2</sup> cos<sup>2</sup>(a)cos<sup>2</sup>(b)-sin<sup>2</sup>(a)sin<sup>2</sup>(b) sin<sup>2</sup>(u)+cos<sup>2</sup>(v) = 1 cos<sup>2</sup>(a)(1-sin<sup>2</sup>(b))-sin<sup>2</sup>(b)(1-cos<sup>2</sup>(a)) = cos<sup>2</sup>(a)-sin<sup>2</sup>(b)cos<sup>2</sup>(a)-sin<sup>2</sup>(b)+cos<sup>2</sup>(a)sin<sup>2</sup>(b) = cos<sup>2</sup>(a)-sin<sup>2</sup>(b)
J jordan83 New member Joined Nov 9, 2005 Messages 15 Nov 11, 2005 #3 more help! cos(a-b)cos(a+b) + sin(a-b)sin(a+b) = 1-2sin^2(b)
pka Elite Member Joined Jan 29, 2005 Messages 11,978 Nov 11, 2005 #4 cos(X)cos(Y)+sin(X)sin(Y)=cos(X−Y) Let X=a−b & Y=a+b.
J jordan83 New member Joined Nov 9, 2005 Messages 15 Nov 11, 2005 #5 Ok. I am still confused on how to solve it. Thanks!