Need Help Solving System of Equations in 3 variables

HawaiianPunch90

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Joined
Oct 2, 2005
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I've done this 4 times, gotten 4 differnt answers, and none of them work..maybe you can help me

Solve for X, Y, and Z

x + y - 2z = 5
x + 2y + z = 8
2x + 3y - z =1
 
x + y - 2z = 5
x + 2y + z = 8
2x + 3y - z =1

Hmmm...I'm not getting any solutions either.
Taking the first eq. and solving for x : x=5-y+2z

Into eq. 2 & 3
(5-y+2z)+2y+z=8
(10-2y+4z)+3y-z=1

Simplify
5+y+3z=8
10+y+3z=1

y+3z=3
y+3z=9

:idea:

Well, since y and z are constants, y+3z can't equal both 3 and 9.

Therefore, there is no solution to this system. Sorry.
 
You don't say what method to use. How about:
Subtract equation 1 from 2
y+3z=3 and
subtract 2 times equation 1 from 3
y+3z=-9
Except for the sign, I agree. It is inconsistant. No solution.
 
we could use any method we want..i was using elimination and my teacher told us none of them were no solution so idk
 
All I can suggest is check the equations 'cause this one is definitly a no solution done two ways. I do know.
BTW, Rahidz missed the sign.
10+y+3z=1
y+3z= -9
 
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